In an ideal heat engine, the absolute temperature of the heater is three times the absolute temperature

In an ideal heat engine, the absolute temperature of the heater is three times the absolute temperature of the refrigerator. The ratio of the work done in one cycle by the gas to the amount of heat received in one cycle by the refrigerator is equal to …?

Let T1 denote the temperature of the heater, and T2 – the temperature of the refrigerator.
Q1 is the amount of heat received by the gas from the heater in one cycle, and
Q2 – the amount of heat given off by the gas to the refrigerator in one cycle.
A – Work performed by the heat engine in one cycle.
It is necessary to find A / Q2

By the condition of the problem, T1 = 3 * T2.
The efficiency of an ideal heat engine can be determined from the equation
k = (T1 – T2) / T1
k = 2 * T2 / (3 * T2) = 2/3
The efficiency is also equal to
k = (Q1 – Q2) / Q1,
(Q1 – Q2) / Q1 = 2/3
From here
3 * Q1 – 3 * Q2 = 2 * Q1
Q1 = 3 * Q2
A = Q1 – Q2 = 3 * Q2 – Q2 = 2 * Q2
A / Q2 = 2