In an ideal heat engine, the temperature of the heater is 420 K, and the temperature of the refrigerator is 280 K.

In an ideal heat engine, the temperature of the heater is 420 K, and the temperature of the refrigerator is 280 K. Find the work done by the machine if 10 ^ 5 kJ of heat is taken from the heater.

To calculate the value of the work performed by the specified machine, we use the equality: Ap / Qn = η = 1 – Tx / Tn, from where we express: Ap = (1 – Tx / Tn) * Qn.

Variables: Tx – abs. refrigerator temperature (Tx = 280 K); Тн – abs. heater temperature (Тн = 420 К); Qн – heat taken from the heater (Qн = 10 ^ 5 kJ).

Let’s perform the calculation: Ap = (1 – Tx / Tn) * Qn = (1 – 280/420) * 10 ^ 5 = 33.3 (3) * 10 ^ 3 kJ = 33.3 (3) MJ.

Answer: The work done by this machine is 33.3 (3) MJ.