In an inductance coil of 40mH, with a uniform disappearance of a current of 2A for 0.01 s, an EMF of self-induction occurs.

To solve the problem, you need to use a formula of the following type:
ε = L * i / t;
The values we know are:
L – 4 * 10 ^ (- 2) H;
i – 2 A;
t – 0.01;
Substitute the values above into the formula:
ε = (4 * 10 ^ (- 2) Gn * 2 A) / 0.01;
Let’s count:
ε = 8.
Answer: ε = 8.



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