In an iron tank with a mass of m = 65 kg, heated by the rays of the Sun to a temperature of t1 = 30 ° C

| February 23, 2021 | education

In an iron tank with a mass of m = 65 kg, heated by the rays of the Sun to a temperature of t1 = 30 ° C, cold water with a mass of M = 300 kg was poured from a well, having a temperature of t2 = 5 ° C. By the evening, the water tank warmed up to a temperature of T = 300 K. Estimate the amount of heat received by the water tank.

Given: m1 (tank) = 65 kg; t1 (tank temp.) = 30 ºС; m2 (water) = 300 kg; t2 (water temp.) = 5 ºС; t (temp. in the evening) = 300 K (27 ºС); Szh (iron) = 460 J / (kg * K); Sv (water) = 4200 J / (kg * K).

1) Temp. in the tank: Czh * m1 * (t1 – t1.2) = Sv * m2 * (t1.2 – t2).

460 * 65 * (30 – t1.2) = 4200 * 300 * (t1.2 – 5).

897000 – 29900t1.2 = 1260000t1.2 – 6300000.

1289900t1.2 = 7197000 and t1.2 = 5.58 ºС.

2) Heat: Q = (Czh * m1 + Sv * m2) * (t – t1.2) = (460 * 65 + 4200 * 300) * (27 – 5.58) = 27629658 J ≈ 27.6 MJ.



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