In an isosceles right triangle, the hypotenuse is 3 cm. Find the acute corners and perimeter of this triangle.

Since the ABC triangle is rectangular and isosceles, the angle at the vertex C is 900, then the angle CAB = CBA = (180 – 90) / = 45.

Since AC = BC, then by the Pythagorean theorem we determine their length.

AC ^ 2 + BC ^ 2 = AB ^ 2.

2 * AC ^ 2 = 9.

AC = BC = 9 / √2 = 4.5 * √2 cm.

Let’s define the perimeter of the triangle ABC.

Ravs = 2 * AC + AB = 9 * √2 + 3 = 3 * (3 * √2 + 1) cm.

Answer: The acute angles of the triangle are 45, the perimeter is 3 * (3 * √2 + 1) cm.