In an isosceles trapezoid ABCD base BC = 12cm, AD = 30cm. Height BH is lowered from top B to base AD. Find HD.

Since, by condition, the trapezoid is isosceles, the height drawn from the top of the obtuse angle divides it into two segments by a larger base, the larger of which is equal to the half-sum of the bases.

НD = (BC + AD) / 2 = (12 + 30) / 2 = 42/2 = 21 cm.

Answer: The length of the НD segment is 21 cm.



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