In an isosceles trapezoid ABCD, the larger base AD is equal to the diagonal.
In an isosceles trapezoid ABCD, the larger base AD is equal to the diagonal. Height BM divided the base AD into segments AM = 6 cm and MD = 9 cm. Find the side and height.
Let’s calculate the length of the larger base. AD = AM + DM = 6 + 9 = 15 cm.
Then, by condition, the diagonal BD = AD = 15 cm.
Triangles ABM and DBM are rectangular, since BM is the height.
From the right-angled triangle DBM, we determine the length of the height of the VM using the Pythagorean theorem.
BM ^ 2 = BD ^ 2 – DM ^ 2 = 15 ^ 2 – 9 ^ 2 = 225 – 81 = 144.
ВM = 12 cm.
In a right-angled triangle ABM, by the Pythagorean theorem, we determine the length of the lateral side AB.
AB ^ 2 = BM ^ 2 + AM ^ 2 = 12 ^ 2 + 6 ^ 2 = 144 + 36 = 180.
AB = 6 * √5 cm.
Answer: The height of the trapezoid is 12 cm, the side is 6 * √5 cm.