In an isosceles trapezoid BCDE, the angle B = 80 degrees. Find the angle KDE if the segment DK
| September 3, 2021 | education
In an isosceles trapezoid BCDE, the angle B = 80 degrees. Find the angle KDE if the segment DK is parallel to the side of the BC.
Angle DEB = CBE = 80, since the angles at the bases of the trapezoid are equal.
The angle DKE = CBE = 80, as the corresponding angles at the intersection of parallel straight lines BC and DK secant BE.
Determine the value of the angle KDE of the triangle KDE.
Angle KDE = 180 – DEK – DKE = 180 – 80 – 80 = 20.
Answer: The value of the KDE angle is 20.
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