In an isosceles trapezoid, one angle is 50 ° greater than the other. Calculate the angles of the trapezoid.

ABCD is an isosceles trapezoid. Angle A = angle D, angle B = angle C. Let’s denote angles A and D as x, then angles B and C will be equal to x + 50.
The sum of all interior angles of any quadrangle is 360 degrees. Then:
angle A + angle B + angle C + angle D = 360 degrees;
x + x + 50 + x + 50 + x = 360;
4x = 360 – 100;
4x = 260;
x = 260/4;
x = 65.
Angle A = angle D = x = 65 degrees, angle B = angle C = x + 50 = 65 + 50 = 115 (degrees).
Answer: angle A = 65 degrees, angle B = 115 degrees, angle C = 115 degrees, angle D = 65 degrees.