In an isosceles trapezoid, the angles are 2: 7. Find the corners of the trapezoid.

univerkov | April 26, 2021 | education

Since the trapezoid ABCD is isosceles, the angles at its base are equal.

Angle BAD = CDB, angle ABC = DCB.

Let the value of the angle BAD be equal to 2 * X0, then, by condition, the value of the angle ABC is equal to 7 * X0.

The sum of the angles of a trapezoid at its lateral side is 180, then:

2 * X + 7 * X = 180.

9 * X = 180.

X = 180/9 = 20.

Angle BAD = CDA = 2 * 20 = 40.

Angle ABC = DCB = 7 * 20 = 140.

Answer: The angles of the trapezoid are 40 and.

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