In an isosceles trapezoid, the base is 6 cm and 14 cm, and the side is 5 cm. Find the area of the trapezoid.

The area of an isosceles trapezoid S = (a + b) / 2 × √ (c ^ 2 – (a – b) ^ 2/4), where a is the upper base, b is the lower base, c is the side.

We get S = (6 + 14) / 2 × √ (25 – (6 – 14) ^ 2/4) = 10 × √ (25 – 16) = 30.



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