In an isosceles trapezoid, the base lengths are 20cm and 30cm, and the acute angle is 45. Find the area of the trapezoid.
Let’s draw the heights between the sides and the smaller base. We get that an acute angle with a degree measure of 45 ° will be equal to another acute angle in a right-angled triangle. The triangle will have equal sides, since the angles at the base are equal.
Let’s find the values of the lateral sides of right-angled triangles through the base difference:
30 – 20 = 10 cm – the sum of two sides that exceed the smaller base and adjacent to the sides.
Hence one of them
10: 2 = 5 cm.
each value is equal to the height, since these are the sides.
h = 5 cm.
We substitute the known values into the formula for the area of a trapezoid:
S = (a + b) h / 2 = ((20 + 30) 5) / 2 = (50 * 5) / 2 = 25 * 5 = 125 cm2 – the area of the trapezoid.
Answer: 125 cm2.