In an isosceles trapezoid, the bases are 8 cm and 48 cm, diagonal is 35 cm Find the perimeter of the trapezoid.

Let’s build the height of the CH trapezoid.

According to the property of the height of an isosceles trapezoid, the length of the segment is DH = (AD – BC) / 2 = (48 – 8) / 2 = 20 cm.

Then the length of the segment АН = АD – DH = 48 – 20 = 28 cm.

In a right-angled triangle ACH, then CH ^ 2 = AC ^ 2 – AD ^ 2 = 35 ^ 2 – 28 ^ 2 = 1225 – 784 = 441.

CH = 21 cm.

From the right-angled triangle СDН we determine the length of the hypotenuse СD.

CD ^ 2 = CH ^ 2 + DH ^ 2 = 441 + 400 = 841.

СD = 29 cm.

Since the trapezoid is isosceles, then AB = CD = 29 cm.

Determine the perimeter of the trapezoid.

Ravsd = (AB + BC + CD + AD) = (29 + 8 + 29 + 48) = 114 cm.

Answer: The perimeter of the trapezoid is 114 cm.



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