In an isosceles trapezoid, the height divides the larger base into segments equal to 5 and 12 cm. Find the middle line of the trapezoid.
1. Let’s designate the height indicated in the condition of the problem BK. It divides the larger base into two segments AK = 5 cm and KD = 12 cm. From the top of C we draw one more height CM.
DM = AK = 5 centimeters.
2. We calculate the length of the lower base of blood pressure:
5 + 12 = 17 centimeters.
3. Calculate the length of the upper base of the aircraft:
BC = KM = 12 – 5 = 7 centimeters.
4. The length of the midline of the trapezoid is equal to half the sum of the bases:
(17 + 7) / 2 = 24/2 = 12 centimeters.
Answer: the length of the middle line of the AVSD trapezoid is 12 centimeters.
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