In an isosceles trapezoid, the height drawn from the apex of the obtuse angle divides the larger base into 5 cm lengths

In an isosceles trapezoid, the height drawn from the apex of the obtuse angle divides the larger base into 5 cm lengths and 15 cm find the base of the trapezoid.

Given:
AVSK – isosceles trapezoid,
BE – top,
AE = 5 centimeters.
EK = 15 centimeters.
Find the length of the bases BC and AK -?
Decision:
Consider the isosceles trapezoid ABSK. She has AB = SK and angle A = angle K, by definition, an isosceles trapezoid. Let’s draw the height of CM.
Right-angled triangles ABE = SCM in hypotenuse and acute angle. Then AE = MK = 5 centimeters.
Therefore EM = EK – MK;
EM = 15 – 5;
EM = 10 centimeters.
The BCME quadrilateral is a rectangle, then BC = EM = 10 centimeters.
Base AK = AE + EK;
AK = 5 + 15;
AK = 20 centimeters.
Answer: 10 centimeters; 20 centimeters.