In an isosceles trapezoid, the sum of the two angles is 204 degrees. Find the sharp corner of the trapezoid.

Since the trapezoid ABCD is isosceles, and the sum of its two angles is 204, since this sum is greater than 180, then this is the sum of the angles with a smaller base.

The angles at the base of an isosceles trapezoid are equal, then the angle ABC + BCD = 204.

Angle ABC = BCD = 204/2 = 102.

The sum of the angles of the trapezoid with its lateral side is 180, then the angle BAD = (180 – ABC) = (180 – 102) = 78.

Answer: The acute angle of the trapezoid is 78.



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