In an isosceles triangle ABC, a height is drawn to the base AC, the length of which is 19 cm, the angle CBD is 43 degrees

In an isosceles triangle ABC, a height is drawn to the base AC, the length of which is 19 cm, the angle CBD is 43 degrees. Determine the length of the segment CD and the angles ABD and ABC.

The height drawn in an isosceles triangle to the base is the bisector and median.

Therefore, angle ABD = angle CBD = 43;

angle ABC = angle ABD + angle CBD = 43 +43 = 86;

CD is found through the tangent of the angle CBD in a right-angled triangle CDB

tg (CBD angle) = CD / BD;

CD = BD * tg (43) = 19 * 0.93 = 17.1.

Answer: 17.1 cm; 43; 86.



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