In an isosceles triangle ABC (AB- base), the angle A at the base of AC is 35.

In an isosceles triangle ABC (AB- base), the angle A at the base of AC is 35. Find the angles at the vertices B and C of triangle ABC

The angles at the base of an isosceles triangle are equal, therefore:

A = B = 35 °;

According to the property of triangles, all its angles in the sum always form 180 °, therefore:

A + B + C = 180 °;

35 ° + 35 ° + С = 180 °;

70 ° + C = 180 °;

C = 180 ° – 70 °;

C = 110 °.