In an isosceles triangle ABC (AB-base), the angle at the apex C is 60. Find the angles at the base AC of this triangle.

According to the properties of an isosceles triangle, the angles at its base are equal to each other:

A = B;

The sum of the angles in any triangle is 180 °; let’s make the equation:

A + B + C = 180 °;

A + B + 60 ° = 180 °;

A + B = 180 ° – 60 ° = 120 °;

A = B = 120 ° / 2 ° = 60 °.



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