In an isosceles triangle ABC (AB = BC), the angle ABC = 44, the height CH meets the bisector BK
| May 31, 2021 | education
In an isosceles triangle ABC (AB = BC), the angle ABC = 44, the height CH meets the bisector BK at point X. Find the angle BXC.
Since BK is a bisector, it divides the angle at the vertex B in half, then the angle ABK = 44/2 = 22.
CH is the height of the triangle, then the triangle BHX is rectangular, in which we determine the value of the angle BHN.
Angle ВХН = (180 – 90 – 22) = 68.
Angles ВХН and ВХС are adjacent angles, the sum of which is 180, then the angle ВХС = (180 – 68) = 112.
Answer: The BXC angle is 112.
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