In an isosceles triangle ABC, angle B = 104 degrees, AD is the height. Find DAC Angle

Since the triangle ABC is isosceles, AB = CB, the angles at the base of the AC are equal.

Angle BAC = BCA.

The sum of the inner angles of the triangle is 180, then the angle BAC = BCA = (180 – ABC) / 2 = (180 – 104) / 2 = 78/2 = 38.

Since AD is the height of the ABC triangle, the ADC triangle is rectangular, and the ADC angle is 90.

The sum of the acute angles of a right-angled triangle is 90, then the angle DAC = 90 – BCA = 90 – 38 = 52.

Answer: The DAC angle is 52.