In an isosceles triangle ABC, angle B is obtuse. Height BD = 8 cm.Find P abc if P abd = 24 cm.

Since triangle ABC is isosceles, its height VD is also the bisector and median of the triangle, then AD = СD.

Ravs = AB + AD + ВD.

24 = AB + AD + 8.

(AB + AD) = 24 – 8 = 16 cm.

The perimeter of the triangle ABC is equal to: Ravs = AB + BC + AC = AB + BC + AD + СD = 2 * (AB + AD) = 2 * 16 = 32 cm.

Answer: The perimeter of triangle ABC is 32 cm.



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