In an isosceles triangle ABC base AC outside apex angle B is 70 degrees. Calculate base angles.

The angle ABC of the triangle is adjacent to the outer angle CBD. Since the sum of adjacent angles is 180, the angle ABC = 180 – CBD = 180 – 70 = 110.

The ABC triangle is isosceles, then its angles at the base of the AC are equal. Angle BAC = BCA.

The sum of the inner angles of the triangle is 180, then (BAC + BCA) = (180 – ABC) = 180 – 110 = 70.

Then the angle BAC = BCA = 70/2 = 35.

Answer: The angles at the base are 35.



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