In an isosceles triangle ABC. In an isosceles triangle ABC with base AB
| September 30, 2021 | education
In an isosceles triangle ABC. In an isosceles triangle ABC with base AB, angle C is 48 degrees. Find the angle between side AB and the height AH of this triangle.
Since the triangle ABC is isosceles, the angles at its base AB are equal, the angle CAB = CBA.
Then СBА = СBД = (180 – АСВ) / 2 = (180 – 48) / 2 = 66.
Since AH is the height, then the triangle ABH is rectangular, then the angle BAH = 180 – AHB – ABH = 180 – 90 – 66 = 24.
Answer: Angle BAH is 24.
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