In an isosceles triangle, ABC is the base of AC. BH-height. Angle A is 30 degrees,

In an isosceles triangle, ABC is the base of AC. BH-height. Angle A is 30 degrees, Angle B is 120 degrees. Find the angles C and ABH.

Since the triangle ABC is isosceles, the angles at its base are equal, the angle BCA = BAC = 30.

The height BH in an isosceles triangle, lowered to its base, is also the median and bisector of the angle. Then the angle АBН = СBН = ABC / 2 = 120/2 = 60.

Answer: Angle C is 30, Angle ABH is 60.



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