In an isosceles triangle ABC, points K and M are the midpoints of the lateral sides AB and BC, respectively.

In an isosceles triangle ABC, points K and M are the midpoints of the lateral sides AB and BC, respectively. BD is the median of the triangle, the angle is mdb = 54 degrees. What is the degree measure of the angle KDB?

Consider ABC: isosceles, => AB = BC, etc. points K and M are the midpoints of these sides, then AK = KВ = ВM = MС., ВD is the median, the angle of ВDM is 54 degrees. Consider the triangles of HPC and АDM: ABC is isosceles, then АD is both bisector and height. , then the angle of the AED = the angle of the internal combustion engine., KВ = ВM, ВD is the common side. This means that the triangles are equal on 2 sides and the angle between them (1 sign), => angle ВDM = angle KDВ = 54gr as the corresponding elements.
Answer: 54gr