In an isosceles triangle ABC, the angle at the base of the AC is 15 degrees and AB = 6cm.

In an isosceles triangle ABC, the angle at the base of the AC is 15 degrees and AB = 6cm. Calculate the distance from apex A to line BC

The distance from the top A to the side BC is the perpendicular to the AD built on the continuation of the BC beyond the top B.

Then the AВD triangle is rectangular.

Since triangle ABC is isosceles, the angle BCA = BAC = 15.

Angle AВD external angle of triangle ABC, the value of which is equal to the sum of two internal angles not adjacent to it. AВD angle = BAC + BCA = 15 + 15 = 30.

In a right-angled triangle ABC, the leg AD lies opposite an angle of 300, then AD = AB / 2 = 6/2 = 3 cm.

Answer: From top A to side BC 6 cm.