In an isosceles triangle ABC, the base angle is 50 degrees. Find the rest of the corners.

1) since a triangle is p / b, by the property of a p / b triangle, the angles at the base are equal (Angle 2 and angle 3)
2) find the sum of the angles at the base
Angle 2 + Angle 3 = 50 ° + 50 ° = 100 °
3) By the theorem on the sum of the angles of a triangle, it follows that the sum of the angles of a triangle = 180 °
Angle 1+ Angle 2+ Angle 3 = 180 °
Find angle 1 (at the vertex)
Angle 1 = 180 ° – 100 ° = 80 °
Answer: angle 1 = 80 °, angle 2 = 50 °, angle 3 = 50 °