In an isosceles triangle ABC, the base of AC is 3 cm larger than its side AB and the perimeter is 24 cm. Find the side AB

Let the length of the lateral side AB = X cm.Since the triangle ABC is isosceles, then BC = AB = X cm.

By condition, AC is 3 cm larger than AB.Then AC = (X + 3) cm.

The perimeter of the triangle ABC is equal to: Ravs = (AB + BC + AC) = 24 cm.

(X + X + X + 3) = 24.

3 * X = 24 – 3 = 21.

X = 21/3 = 7 cm.

AB = 7 cm.

Answer: The length of the lateral side AB is 7 cm.



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