In an isosceles triangle ABC, the height BD is drawn to the base of the AC. The length of the height is 10.5 cm
| November 30, 2020 | education
In an isosceles triangle ABC, the height BD is drawn to the base of the AC. The length of the height is 10.5 cm, the length of the lateral side is 21 cm. Determine the angles of this triangle.
Since the triangle ABC is isosceles, the angle BAC = the angle of the BCA
21: 10.5 = 2, therefore the angle BAC = BCA = 30 °
angle ABC = 180 ° – (BAC + BCA) = 180 ° – 60 ° = 120 °
Answer: ∡ BAC = 30 °; ∡ BCA = 30 °; ∡ ABC = 120 °
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