In an isosceles triangle ABC, the height BD is drawn to the base of the AC. The length of the height is 12.8 cm

| December 1, 2020 | education

In an isosceles triangle ABC, the height BD is drawn to the base of the AC. The length of the height is 12.8 cm, the length of the lateral side is 25.6 cm. Determine the angles of this triangle. ∡ BAC ∡ BCA = ∡ ABC

The height drawn in an isosceles triangle to the base is also a median and a bisector. Hence, BD divides the angle B in half.
At the intersection of the height and the base of the AC, right angles are formed ADB = BDC = 90 °
If the leg in a right-angled triangle is 2 times less than the hypotenuse, then the angle opposite this leg is 30 °
Because the angles at the base are equal in an isosceles triangle, then the angles BAC = BCA = 30 °
By the sum of the angles of the triangle = 180 °, it means 180- (30 + 30) = 120 ° – angle ABC
Answer: angle BAC = angle BCA = 30 ° angle B = 120 °



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