In an isosceles triangle ABC, the height BH is 12 cm, and the base AC is 3 times the height BH. Find the area of triangle ABC.

Let us determine the length of the AC base, which, according to the condition, is three times greater than the HВ height.

AC = 3 * ВН = 3 * 12 = 36 cm.

Let’s define the area of the triangle ABC.

Savs = AC * ВН / 2 = 36 * 12/2 = 216 cm2.

Answer: The area of the triangle ABC is 216 cm2.



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