In an isosceles triangle ABC, the median to the AC rigging is drawn. On this median point D is chosen so that

In an isosceles triangle ABC, the median to the AC rigging is drawn. On this median point D is chosen so that the ADB angle is 130 degrees. Find the corner of the BDC.

Let us prove the equality of the triangles AВD and СВD.

Since the triangle ABC is isosceles, then AB = BC. The median BH is also the bisector of the ABC angle, then the ABD = CBD angle. The segment BD is common for triangles, then triangles ABD and CBD are equal on two sides and the angle between them. Then the angle BDC = ADB = 130.

Answer: The BDC angle is 130.