In an isosceles triangle ABC, the segment BD is the median drawn to the base

In an isosceles triangle ABC, the segment BD is the median drawn to the base. Find the perimeter of triangle ABC if ABD = 12 cm, BD = 4 cm.

The median divides the base of AC in half, AD = CD = AC / 2.

The perimeter of the triangle ABC is equal to: Ravs = AB + BC + AC = AB + BC + AD + CD = 2 * AB + 2 * AD = 2 * (AB + AD).

The area of the triangle ABD is equal to: Ravd = AB + BD + AD = 12 cm.

(AB + AD) = 12 – BD = 12 – 4 = 8 cm.

Then Ravs = (AB + AD) * 2 = 8 * 2 = 16 cm.

Answer: The perimeter of triangle ABC is 16 cm.



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