In an isosceles triangle abc to the base of ac, the median BM is drawn, it is known that the angle ABM

In an isosceles triangle abc to the base of ac, the median BM is drawn, it is known that the angle ABM = 40 degrees, the angle BAC = 50 degrees, find the angles of the triangle MBC

In an isosceles triangle, the angles at the base are equal, which means that in this isosceles triangle, the angle BAC is equal to the angle of the BCA. Since we are given that the angle BAC = 50 °, then the angle BCA = 50 °;

In an isosceles triangle, the median drawn to the base is also the height and bisector. So we can say that in the given triangle MBC the angle BMC = 90 °, and also the angle ABM is equal to the angle MBC; Therefore, the angle MBC = 40 °.

Answer: In the MBC triangle, the angles are: 90 °, 40 °, 50 °.