In an isosceles triangle ABC with a base AB, a bisector CD is drawn, the angle ACD is equal to 68 °
| July 19, 2021 | education
In an isosceles triangle ABC with a base AB, a bisector CD is drawn, the angle ACD is equal to 68 °, which is equal to the angle ABC.
Since the triangle is isosceles, the bisector CD is also the height of the triangle, and then the triangles ACD and BCD are rectangular.
The angle CAD in triangle ACD will be equal to: CAD = 180 – ACD – ADC = 180 – 68 – 90 = 22.
In an isosceles triangle, the angles at the base are equal, the angle ABC = CAD = 22.
Answer: Angle ABC is 22.
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