In an isosceles triangle ABC with a base AC, the side AB is 14, and cos A = √195 divided by 14.
| March 29, 2021 | education
In an isosceles triangle ABC with a base AC, the side AB is 14, and cos A = √195 divided by 14. Find the height referred to the base.
Determine the sine of angle A.
Sin2A + Cos2A = 1.
Sin2A = 1 – Cos2A = 1 – (√195 / 14) ^ 2 = 1 – 195/196 = 1/196.
SinA = 1/14.
Then in a right-angled triangle ABN, BN = AB * SinA = 14 * 1/14 = 1 cm.
Answer: The length of the BH height is 1 cm
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