In an isosceles triangle ABC with a base AC, the side AB is 14, and the cosine of angle A
| May 24, 2021 | education
In an isosceles triangle ABC with a base AC, the side AB is 14, and the cosine of angle A is equal to the root of 3 divided by 2 (written as a fraction). Find the height drawn to the base.
Determine the sine of angle A.
Sin2A + Cos2A = 1.
Sin2A = 1 – Cos2A = 1 – (√3 / 2) 2 = 1 – 3/4 = 1/4.
SinA = 1/2.
Then in a right-angled triangle ABH, BH = AB * SinA = 14 * 1/2 = 7 cm.
Answer: The length of the BH height is 7 cm.
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