In an isosceles triangle ABC with base AB = 3, tg A = 5. Find the height dropped by AB

Since triangle ABC, by condition, is isosceles, then its height CH is also the median of the triangle, then AH = BH = AB / 2 = 3/2 = 1.5 cm.

The ACН triangle is rectangular, in which tgCAH = CH / AH, then CH = AH * tgCAH = 1.5 * 5 = 7.5 cm.

Answer: The height of the triangle is 7.5 cm.



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