In an isosceles triangle ABC with base AC, the angle A is 40. Find the remaining angles.

Since the triangle ABC is isosceles, AB = CB, the angles at the base of the AC are equal.

Angle BAC = BCA = 40.

The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – BAC – BCA) = (180 – 40 – 40) = 100.

Answer: The angles of the triangle ABC are 40, 40, 100.



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