In an isosceles triangle ABC with base AC, the lateral side is 15 and cosA = 0.6. find the height drawn to the base

Since triangle ABC is isosceles (by the problem statement), the height is the median drawn to the side AC. Then:

AH = 1/2 * AC = 1/2 * 15 = 15/2.

Triangle ABH is rectangular (since AH is height), then, using the Pythagorean theorem, we get:

AH = AH cos (A) = 15/2 * 0.6 = 5.

Answer: the required height is 5.



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