In an isosceles triangle ABC with base AC, the lateral side is 2 times the base

In an isosceles triangle ABC with base AC, the lateral side is 2 times the base, and the perimeter of the triangle is 60 cm. Find the sides of the triangle.

Since, according to the condition, triangle ABC is isosceles, the lengths of its lateral sides are equal, AB = CB.

Let the length of the sides be 2 X cm, AB = CB = 2 * X cm, then the base length AC = AB / 2 = 2 * X / 2 = X cm.

Let’s define the perimeter of the triangle ABC.

Ravs = (AB + CB + AC) = (2 * X + 2 * X + X) = 60.

5 * X = 6.

X = AC = 60/5 = 12 cm.

Then AB = CB = 2 * AC = 2 * 12 = 24 cm.

Answer: The sides of the triangle are 12 cm, 24 cm, 24 cm.