In an isosceles triangle ABC with base AC, the length of its median BT is 5 cm.

In an isosceles triangle ABC with base AC, the length of its median BT is 5 cm. The perimeter of triangle ABC is 50 cm. Find the perimeter of triangle BTC.

Since BT is the median of the triangle ABC, then AT = CT = AC / 2.

The perimeter of the triangle ABC is:

Ravs = AB + BC + AC = (AB + AT) + (BC + CT) = 50.

Since the triangle ABC is isosceles, then (AB + AT) = (BC + CT), and then:

Ravs = 2 * (BC + CT) = 50.

BC + CT = 50/2 = 25 cm.

Then Рвтс = (ВС + CT) + ВТ = 25 + 5 = 30 cm.

Answer: The perimeter of the BTC triangle is 30 cm.