In an isosceles triangle ABC with base AC, the side AB is 32√3 and the cos of angle A is 1/2. Find the height drawn to the base.

Let us determine from the table of trigonometric values the degree value of the angle A, which is located in the triangle ABC:

cos A = 1/2 corresponds to an angle with a degree value equal to 60 °.

Using the same table of trigonometric values, we find what is equal to the sin of an angle with a degree value equal to 60 °:

sin A = √3 / 2.

Determine how many centimeters the height drawn to the base equals, knowing that the length of the AB side is 32√3:

32√3 * √3 / 2 = 48.

Answer: The length of this height is 48 centimeters.