In an isosceles triangle ABC with base AC, the sum of the angles A and C is 156 degrees. Find the angles of triangle ABC.

Since triangle ABC is isosceles, and AC is its base, the angle BAC = BCA.

By condition, the sum of the angles (BAC + BCA) = 156.

Then the angle BAC = BCA = 156/2 = 78.

The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – BAC – BCA) = (180 – 78 – 78) = 24.

Answer: The angles of the triangle ABC are equal to 24, 78, 78.

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