In an isosceles triangle ABC with base BC, the midpoint of side AC

In an isosceles triangle ABC with base BC, the midpoint of side AC meets base BC at point M. Find the angle CAM if the angle ABC = 43 degrees

Since the triangle ABC is isosceles, the angle ACB = ABC = 43.

The segment ME is the midpoint perpendicular, therefore, AE = CE, and ME is the perpendicular to AC.

For the ACM triangle, the ME segment is the height and the median, then the ACM triangle is isosceles with the AC base, and then the angle CAM = ACM = ACB = 43.

Answer: The CAM angle is 43.