In an isosceles triangle ABC with the base of AC, a bisectrix BD of 8 cm is drawn.

In an isosceles triangle ABC with the base of AC, a bisectrix BD of 8 cm is drawn. Find the perimeter of BDC if the perimeter of ABD is 18 cm.

Since the triangle ABC is isosceles, then AB = BC, and its bisector ВD drawn to the base is also the height and median of the ABC triangle.

Then AD= СD = AC / 2, and the triangles of the AВD and ВСD are rectangular.

Rectangular triangles AСD and ВСD are equal in leg and hypotenuse, then their perimeters will be equal.

Rvds = Ravd = 18 cm.

Answer: The perimeter of the ВDС triangle is 18 cm.



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