In an isosceles triangle ABC with the base of the AC from the vertices A and B, bisectors are drawn forming when crossing

In an isosceles triangle ABC with the base of the AC from the vertices A and B, bisectors are drawn forming when crossing an angle of 100 degrees, find the angles of the triangle.

Let the angle ACB = X0, then the angle ABC = (180 – 2 * X) 0.

Then the angle BCO = X / 2, the angle OBC = ABC / 2 = 90 – X.

In the BOC triangle, the sum of the angles is 180.

100 + X / 2 + 90 – X = 180.

X / 2 = 10.

X = ACB = 20.

Angle ABC = (180 – 20 – 20) = 140.

Answer: The angles of the triangle are 20, 20, 140.