In an isosceles triangle ABC with the base of the AC, the angle B = 65 *. Find the rest of the corners of the triangle.

B = C = 65 * (isosceles triangle, therefore, the angles at the base are equal).
And since the sum of the angles of the triangle is 180 *, then A = 180- (65 + 65) = 50 *
Answer: 65, 65, 50



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