In an isosceles triangle CDE, angle ABC = angle CBE, prove that triangles ADC and CEB are equal.

In this case, the first sign of the equality of the triangle is suitable, namely, “If the two sides and the angle between them of one triangle are respectively equal to the two sides and the angle between them of another triangle, then such triangles are equal.” In this case, the angle ABC = CEB, therefore the triangle ADC is equal to the triangle CEB



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